The shear modulus ($G$) is related to Young's modulus ($E$) and Poisson's ratio ($\nu$) by the following equation: $G = \frac{E}{2(1 + \nu)}$ . This relationship is a fundamental one in the theory of linear elasticity, connecting the modulus that describes a material's resistance to shear deformation ($G$) with the modulus describing its resistance to axial deformation ($E$) and its lateral contraction properties ($\nu$).
This relationship is a core equation in the field of linear elasticity for isotropic (having the same properties in all directions) and homogeneous materials.
The relationship is $E = 2G(1 + \nu)$, which is algebraically rearranged to the form you cited: $G = \frac{E}{2(1 + \nu)}$.
This formula confirms that for any isotropic elastic material, only two of the three constants are independent. If you know any two (for example, $E$ and $\nu$), you can calculate the third ($G$).
The relationship is derived by analyzing a simple shear deformation ($\tau$) and showing that it can be represented as a combination of a tension stress ($\sigma_1$) and a compression stress ($\sigma_2$) at 45-degree angles.
By expressing both the shear stress ($\tau$) and the axial stresses ($\sigma_1, \sigma_2$) in terms of strains using $G$ (for shear) and $E$ and $\nu$ (for tension/compression), the two descriptions must be mathematically equal, which leads directly to the equation:
$$ \mathbf{E} = 2\mathbf{G}(1 + \mathbf{\nu}) $$
How is the shear modulus related to Young's modulus and Poisson's ratio-L.mp4