The problem demonstrated how coordinate scaling affects the geometry of space, starting with the transformation $y^3=2 x^3$. This scaling leads to a diagonal metric tensor where only the $g_{33}$ component is altered, becoming 1 / 4, resulting in a metric determinant of $g=1 / 4$. The key implication is how this value scales the vector calculus operations: the Levi-Civita density $\eta^{a b c}$, crucial for the cross product, is scaled by $1 / \sqrt{g}=2$. Consequently, the contravariant components of the cross product, $(v \times w)^a=\eta^{a b c} v_b w_c$, are simply twice the magnitude of the standard Cartesian cross product involving the covariant components of the vectors, illustrating the general principle that all tensor operations in non-Cartesian coordinates must incorporate factors derived from the metric determinant.
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$\complement\cdots$Counselor
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Metric Tensor Calculation (Diagonal Metrics):
$$ g_{a a}=\sum_i\left(\frac{\partial x^i}{\partial y^a}\right)^2 $$
Metric Determinant and Volume Element:
$$ g=1 \cdot 1 \cdot \frac{1}{4}=\frac{1}{4} $$
Relating Levi-Civita Density and Symbol:
$$ \eta^{a b c}=\frac{1}{\sqrt{g}} \varepsilon^{a b c} $$
Cross Product in General Coordinates:
$$ (v \times w)^a=\eta^{a b c} v_b w_c $$
$$ (v \times w)^1= 2 \left( v _{ 2 } w _{ 3 }- v _{ 3 } w _{ 2 }\right) $$
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